For the function f(x)= 5x-7sin(x), 0<x<pi
I need to find the open interval(s) f is increasing and decreasing on.
I first found the derivative which is 5-7cos(x) and then found the zeros of the function which is arccos(5/7)
From this I found the increasing open interval to be ((arccos(5/7)),inf) and decreasing open interval to be (-inf, (arccos(5/7)))
Somehow this is incorrect could someone tell me what I did wrong?