Hi I have another area problem
r = 3cos x and r = 1 + cos x
so A i= integral sign (S) a= 0; b=pi/3 ((3cos x)^2 - (1+cos x)^2) dx
which works out to S a=0;b= pi/3 (8cos^2 x - 2 cos x - 1) dx
This one is actually in my answer sheet and it gives the next step as
S a=0; b=pi/3 (4(1+cos 2x) - 2 cos x - 1) dx
Where does the 4(1+cos 2x) from????
Insight is appreciated