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Math Help - Kind of tough integral

  1. #1
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    Kind of tough integral

    If anyone knows how to get the value of k, please show the steps.

     <br />
V = 2\pi \int_0^1 {(x - k)\sqrt {{{(x + 4)}^2} - 16} dx} = 10{m^3}<br />
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  2. #2
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    Quote Originally Posted by baseballman View Post
    If anyone knows how to get the value of k, please show the steps.
     <br />
V = 2\pi \int_0^1 {(x - k)\sqrt {{{(x + 4)}^2} - 16} dx} = 10{m^3}<br />
    Go to this website Wolfram|Alpha
    In the input window, type in this exact expression: integrate (x-k)sqrt[(x+4)^2-16]dx (you can copy & paste)
    Click the equals bar at the right-hand end of the input window.
    Be sure you click ‘show steps’ to see the solution
    .
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