Hi

The parametric equations are x= e^t -1 and y=2e^t +3t

So dx/dt = e^t and dy/dt = 2e^t + 3

Let P be a point of curve C. Suppose the tangent line to C at the point P has slope 7. Find the coordinates of P

dy/dx = (2e^t + 3)/e^t = 7 so 7= 2+ 3/e^t and e^t = 3/5

Now I can then figure out that x = -2/5 but how do I figure out what y is?

y = 2e^t + 3t => y = 2(3/5) + 3t

Help please!

Thanks

Calculus beginner