If I understand this you're looking for a function such that . If this is the case, simply derive and check that your answer is correct (It is, if this is what you meant anyway).
Alright so I have no idea what im doing and I cant seem to figure it out
from what I can tell a vector field is generally, although not always, just the gradient of the potential field
so I have this question to answer:
Find a potential for the vector field F by inspection.
F = <yz^2,xz^2,2xyz>
i thought it would simply be phi(x)=xyz^2
thought this is not that case
what am i doing wrong?