1. ## limit/l'hopital

lim
x->1 $\frac{3ax-3a}{2(x-1)}$

^I think the error is here, because if I simplify it, there is no where to do l'hopital.
x->1 $\frac{3a(x-1)}{2(x-1)}$

x->1 $\frac{3a}{2}$

2. The derivative of the top line should be...
$3ax^{3a-1} - 3a$

3. so $f'$ of numerator and denominator $= \frac{(3a)(3a -1)[(3ax)^(3a-2)]}{2}$ ?

4. I simplified it to this,:
but no luck.

5. Originally Posted by hazecraze

lim
x->1 $\frac{3ax-3a}{2(x-1)}$

^I think the error is here, because if I simplify it, there is no where to do l'hopital.
x->1 $\frac{3a(x-1)}{2(x-1)}$

x->1 $\frac{3a}{2}$
$\lim_{x \to 1}\frac{x^{3a} - 3ax + 3a - 1}{(x - 1)^2} = \lim_{x \to 1}\frac{3ax^{3a - 1} - 3a}{2(x - 1)}$.

This is still indeterminate, so use L'Hospital again...

$= \lim_{x \to 1}\frac{3a(3a - 1)x^{3a - 2}}{2}$

$= \frac{3a(3a - 1)}{2}$

$= \frac{9a^2 - 3a}{2}$.