How do you solve (1 - (cosx)^3)/x^2 as x -> 0? I tried to use l'Hospital rule but it didn't help.
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no , l'Hospital rule should help you. use it two times and you can get the answer
you only need L'Hopitals Rule once: (1 - (cosx)^3)/x^2 differentiate: 3cos^2(x) {sin(x)/2x} and lim 3cos^2(x) {sin(x)/2x} = 3/2 as lim sin(x)/x = 1
Originally Posted by antero How do you solve (1 - (cosx)^3)/x^2 as x -> 0? I tried to use l'Hospital rule but it didn't help. You can calculate this limit without L'Hospital's rule:
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