I have ,

= second quadrant of

I changed to polar coordinates:

Do I evaluate the integral like this?

Printable View

- November 13th 2009, 01:56 AMbillymarea; polar coordinates
I have ,

= second quadrant of

I changed to polar coordinates:

Do I evaluate the integral like this?

- November 13th 2009, 02:00 AMjeneverboy
I think your boundaries are correct.

- November 13th 2009, 02:57 AMgalactus
Don't forget about that extra r when using polar integration.

- November 13th 2009, 05:30 AMbillym
Should the answer be the same as or am I missing the point here?

- November 13th 2009, 07:17 AMbillym
Or rather, that is R. Which is basically the upper left portion of a doughnut. But what does the area of integration look like?

- November 14th 2009, 01:50 AMbillym
Pardon me for being the village idiot, but could somebody please answer this one question for me:

When sketching the area of integration, do I just sketch , or do I have to consider ? - November 14th 2009, 03:51 AMrn443
- November 14th 2009, 05:03 AMbillym
yeah I realized that last night. Anyway, I've got the right answer now. Thanks dudes.