Please post the original function in a clear manner.
Find the derivative of the function. y = 2^3 - x^2
cant get the right answer, i think its partly due to me not knowing the derivative of 2^x.
I did:
outside function = 2^x
outside deriv.= 2^xlog(2) <----this is what i got from an online deriv. calc
inside = 3-x^2
inside deriv = -2x
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I dont undersand the whole inside and outside thing you got going on, but i know that since it is an additive functionjust take the derivative of each term. Like you did in the inside part and put them together.
The answer would be:
y'= 3x^2-2x
which folows f(x)= x^(n)
nx^(n-1)