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Math Help - take the second derivative..

  1. #1
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    Exclamation take the second derivative..

    take the second derivative of x^2y^2-2x=3
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  2. #2
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    Quote Originally Posted by thatonegurl View Post
    take the second derivative of x^2y^2-2x=3
    show us the first derivative ... you need that to get the second.
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  3. #3
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    I'm confused with derivatives all together.

    As far as the first derivative, I got as far as 2x2yy'-2=0

    I'm not sure what to do after that, and I don't even know if that is right.
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  4. #4
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    Quote Originally Posted by thatonegurl View Post
    I'm confused with derivatives all together.

    As far as the first derivative, I got as far as 2x2yy'-2=0

    I'm not sure what to do after that, and I don't even know if that is right.
    you need to use the product rule for the first term ...

    \frac{d}{dx}(x^2y^2-2x = 3)

    x^2 \cdot 2y \cdot y' + y^2 \cdot 2x - 2 = 0

    solve for y' , then take the derivative again.
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