# Math Help - slope of the tangent line...!?

1. ## slope of the tangent line...!?

If y=ln(x^2) find:

The equation to the tangent line where x=e

The point where the slope of the tangent line is 2/3

HELP.

2. Originally Posted by puravida12
If y=ln(x^2) find:
The equation to the tangent line where x=e
The point where the slope of the tangent line is 2/3.
$y = \ln \left( {x^2 } \right) = 2\ln (x)\, \Rightarrow \,y' = \frac{2}
{x}$

3. Thanks, but what exactly does it mean when it says "where x=e"?

and how do I find the point when given "2/3" as a tangent line?

4. Originally Posted by puravida12
what exactly does it mean when it says "where x=e"?
Sorry but one does not expect that sort of question from someone in a calculus course.
$y = \ln \left( {x^2 } \right),\,x = e\, \Rightarrow \,y = 2$

5. ...what is that supposed to mean?
thank you, sorry, I was confused.