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Math Help - slope of the tangent line...!?

  1. #1
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    Exclamation slope of the tangent line...!?

    If y=ln(x^2) find:

    The equation to the tangent line where x=e

    The point where the slope of the tangent line is 2/3

    HELP.
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  2. #2
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    Quote Originally Posted by puravida12 View Post
    If y=ln(x^2) find:
    The equation to the tangent line where x=e
    The point where the slope of the tangent line is 2/3.
    y = \ln \left( {x^2 } \right) = 2\ln (x)\, \Rightarrow \,y' = \frac{2}<br />
{x}
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  3. #3
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    Thanks, but what exactly does it mean when it says "where x=e"?

    and how do I find the point when given "2/3" as a tangent line?
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    Quote Originally Posted by puravida12 View Post
    what exactly does it mean when it says "where x=e"?
    Sorry but one does not expect that sort of question from someone in a calculus course.
    y = \ln \left( {x^2 } \right),\,x = e\, \Rightarrow \,y = 2
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  5. #5
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    ...what is that supposed to mean?
    thank you, sorry, I was confused.
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