If an object is launched straight up into the air from a starting height ho feet , then the height of the object after t seconds is approximately

h=-16t^2 + Vot+ho feet, where Vo is the initial velocity of the object.Find the starting height and the initial velocity of an object that attains a maximum height of 412 feet five seconds after being launched.

here, ho and Vo is like h(knot)V(knot).Pls don't be confused.