Figured it out! The answer is: (±√2, 0), (±√2, 1/4)
A rectangle has one side on the x-axis and two vertices on the curve y=1/(2+x^2). Find the vertices of the rectangle with maximum area.
I put one of the corners at the origin, which I'm assuming is wrong, because I got (0,0),(2^(1/2),0),(2^(1/2),1/4),(0,1/4), which is incorrect.
Help, please!