how do you solve this simultaneous equations?
sinh x + sinh y = 25/12
cosh x - cosh y = 5/12
You could try writing $\displaystyle \sin, \cos, \sinh, \cosh$ in their exponential form.
$\displaystyle \sinh{x} = \frac{e^{x}-e^{-x}}{2}$
$\displaystyle \cosh{x} = \frac{e^{x}+e^{-x}}{2}$
$\displaystyle \sin{x} = \frac{e^{ix}-e^{-ix}}{2i}$
$\displaystyle \cos{x} = \frac{e^{ix}+e^{-ix}}{2}$
If you then multiply your second equation by 5 then you can set the two equal to one another.
I should just add that $\displaystyle i$ is a constant where $\displaystyle i = \sqrt{-1}$
having using your mtd, i ended up with 2e^x + 2 e^-x = 3e^y -2e^y.
i tried to let e^x = a and e^y =b and then i got
2a + 2(1/a) = 3( b) - 2(1/b)
solving a as a quadratic eqn, i got a and b to be complex numbers..
which according to my notes, it is wrong as the answer should be real values.
did i do sth wrong?