Find the inflection points of (x+2)(x-4)^2
i found the second derivative which is very long
2(x-4)2(x-4)(x+2)+(x-4)^(2)*2(x+2)+2(x-4)=0
I got one inflection point which is 4 but there must be others cause my online hw says its wrong
Find the inflection points of (x+2)(x-4)^2
i found the second derivative which is very long
2(x-4)2(x-4)(x+2)+(x-4)^(2)*2(x+2)+2(x-4)=0
I got one inflection point which is 4 but there must be others cause my online hw says its wrong
I don't know how you calculated the second derivative, but that answer is very wrong. The easiest way to differentiate $\displaystyle (x+2)(x-4)^2$ twice is probably to multiply it out first: $\displaystyle (x+2)(x-4)^2 = (x+2)(x^2-8x+16) = x^3 -6x^2 +32$. That should be easy to differentiate.