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Math Help - Find relative extrema

  1. #1
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    Find relative extrema

    First off, does this mean find relative min and max?

    y = x^3 - 3x^2 + 3x - 1

    Do I find y' , then set it to 0 and solve for x? That is the min

    Do I find y'', then set it to 0 and solve for x? That is the max

    I don't need anyone to do this...just explain how to go about it please.

    Thanks.
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  2. #2
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    Quote Originally Posted by jzellt View Post
    First off, does this mean find relative min and max? <<<<<< Yes

    y = x^3 - 3x^2 + 3x - 1

    Do I find y' , then set it to 0 and solve for x? That is the min <<<<<<< No. You determine the x-coordinate of the extremum, maximum or minimum.

    Do I find y'', then set it to 0 and solve for x? That is the max <<<<<< No. With y'' = 0 you determine the point of inflection. You can distinguish the min and max using the x-coordinates of the extrema as argumant in y''

    I don't need anyone to do this...just explain how to go about it please.

    Thanks.
    ...
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  3. #3
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    So, I guess I'm still a bit confused. How should I go about finding, say just the relative min with the function given?
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  4. #4
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    Quote Originally Posted by jzellt View Post
    So, I guess I'm still a bit confused. How should I go about finding, say just the relative min with the function given?
    Solve dy/dx = 0 for x. That gives the x-coordinates of all stationary points. Test the nature of the stationary points (use either the sign test or the second derivative test).

    Your class notes and/or textbook should have several examples of this ....
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