Can someone kindly help me with this math problem for my calculus class.

I'm sorry I do not have anything to post the proper form of the question (such as square root symbols) but i will try to do my best.

Find lim x--> 6 [Squareroot(x-2) - 2] / (x-6) note** the (x-2) is under the root and then the -2 is outside

now my textbook says you have to multiply the numerator and denominator by Squareroot (x-2) + 2

i understand the we multiply the numerator and denominator by square root (x-2) .. but how come + 2 and not -2?

Also can someone kindly explain how to get to teh final answer? with explanation in each step. thank you very much.