Need some help.
Suppose that f: [0,2] -> [0,4] is continuous. Use the IVT to show that there is an x in [0.2] such that f(x)=2x.
Was given this hint to try and use g: [0,2] -> R defined by g(x)= f(x)-2x. this doesn't seem to help me much.
Any help would be greatly appreciated!