Hello, rawkstar!

The directions are not clear.

I assume that problem came with a labeled diagram.

A winch at the top of a 12 m building pulls a pipe of the same length to a vertical position.

The winch pulls the rope at a rate of -0.2 meters per second.

Find the rate of vertical change and the rate of horizontal change at the end of the pipe when $\displaystyle y=6$. First of all, what is $\displaystyle y$ ?

And are they asking for the changes at the ends of the pipe?

I'm trying to envision the problem.

The pipe is lying horizontally on the ground, perpendicular to the wall of the building..

The rope is attached to the near end of the pipe. Code:

W
- - * *
| :
| :
| :
12 | :r
| :
| :
| :
- - * - o * * * * * * o - -
A 12 B

The winch is at $\displaystyle W.$

The pipe is $\displaystyle AB = 12$.

The length of the rope is $\displaystyle r$.

As the rope gets shorter,

. . the top of the ladder $\displaystyle (A)$ is raised straight up,

. . and the bottom of ladder $\displaystyle (B)$ approaches the building.

Code:

W
- - * *
| :
| :r
| :
12 | o A
| : *
| y: *
| : *
- - * - * - - - o - -
C x B

I would guess that we are concerned with $\displaystyle \frac{dy}{dt}$ and $\displaystyle \frac{dx}{dt}$