Hi, I have been trying to solve this limit for past 4 hours, and I can't figure it out. Can anyone guide me ?
lim x->0 [1/x - 1/((e^x)-1)]
without L'Hosptial, without boundaries
it should be: 1/2; use lim x->0 [((e^x) -1)/x = 1]
sorry for wrong topic name, I messed it up, I'm new here.