First of all, hi everyone, I'm new to this forum

I'll cut to the chase. Q: Let $\displaystyle f(x) = \frac{1}{\sqrt{x}} + 2x^2, x>0 $. Find f'(x) using the definition of the derivative.

$\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}{h}= \lim_{h\to0}\frac{\frac{1}{\sqrt{x+h}}+2(x+h)^2 -\frac{1}{\sqrt{x}}-2x^2}{h} $ Clueless on how to simplify this.