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Math Help - free body falling

  1. #1
    Junior Member
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    Exclamation free body falling

    This is quite a lot of Physics but I didn't find any where else to post this and you people were the only people who could help.

    If somebody can please help me out.


    Q.
    A body moving with uniform acceleration travels 24m in the 6th second and 44m in the 11th second. Find
    i) Acceleration
    ii) Initial velocity of the body


    Please guys. If anybody with the knowledge of Physics or the answer to this question can help me


    2 things
    It isn't 6 and 11 seconds, it is 6th and 11th second.

    I need correct statements. As in the correct formula and stuff like that.
    Because I think I may have gotten the answer, but I'm screwing up in my statements and my teacher demands everything perfect.


    Examinations are coming in 10-15 days and this is all practice. Please help me out. PLEASE!
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  2. #2
    MHF Contributor
    Joined
    Apr 2005
    Posts
    1,631
    Quote Originally Posted by Ruler of Hell View Post
    This is quite a lot of Physics but I didn't find any where else to post this and you people were the only people who could help.

    If somebody can please help me out.


    Q.
    A body moving with uniform acceleration travels 24m in the 6th second and 44m in the 11th second. Find
    i) Acceleration
    ii) Initial velocity of the body


    Please guys. If anybody with the knowledge of Physics or the answer to this question can help me


    2 things
    It isn't 6 and 11 seconds, it is 6th and 11th second.

    I need correct statements. As in the correct formula and stuff like that.
    Because I think I may have gotten the answer, but I'm screwing up in my statements and my teacher demands everything perfect.


    Examinations are coming in 10-15 days and this is all practice. Please help me out. PLEASE!
    Hope I have time. I'm super slow in typing.

    Let Vo = initial velocity, in m/sec.
    And a = constant acceleration, in m/sec/sec.
    And s = distance travelled, in m.

    s = Vo*t +(1/2)a(t^2) ---------from memory, but I can derive that if you like.

    At the 6th second, or 6 seconds from the body when traveling at Vo,
    s = 24 m
    24 = Vo(6) +(1/2)a(6^2)
    24 = 6Vo +18a
    4 = Vo +3a --------------(1)

    At the 11th second, or 11 seconds from the body when traveling at Vo,
    s = 24 +44 = 68 m
    68 = Vo(11) +(1/2)a(11^2)
    136 = 22Vo +121a -------------(2)

    You have 2 independent equations with two unknowns. Solve them simultaneously and you should get
    a = 48/55 m/sec/sec
    Vo = 4 -3a = 76/55 m/sec

    No time to check in details. Gotta go. If something is wrong, I'd get to that in about 11 hours or later. Sorry.
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