# Thread: free body falling

1. ## free body falling

This is quite a lot of Physics but I didn't find any where else to post this and you people were the only people who could help.

Q.
A body moving with uniform acceleration travels 24m in the 6th second and 44m in the 11th second. Find
i) Acceleration
ii) Initial velocity of the body

Please guys. If anybody with the knowledge of Physics or the answer to this question can help me

2 things
It isn't 6 and 11 seconds, it is 6th and 11th second.

I need correct statements. As in the correct formula and stuff like that.
Because I think I may have gotten the answer, but I'm screwing up in my statements and my teacher demands everything perfect.

Examinations are coming in 10-15 days and this is all practice. Please help me out. PLEASE!

2. Originally Posted by Ruler of Hell
This is quite a lot of Physics but I didn't find any where else to post this and you people were the only people who could help.

Q.
A body moving with uniform acceleration travels 24m in the 6th second and 44m in the 11th second. Find
i) Acceleration
ii) Initial velocity of the body

Please guys. If anybody with the knowledge of Physics or the answer to this question can help me

2 things
It isn't 6 and 11 seconds, it is 6th and 11th second.

I need correct statements. As in the correct formula and stuff like that.
Because I think I may have gotten the answer, but I'm screwing up in my statements and my teacher demands everything perfect.

Examinations are coming in 10-15 days and this is all practice. Please help me out. PLEASE!
Hope I have time. I'm super slow in typing.

Let Vo = initial velocity, in m/sec.
And a = constant acceleration, in m/sec/sec.
And s = distance travelled, in m.

s = Vo*t +(1/2)a(t^2) ---------from memory, but I can derive that if you like.

At the 6th second, or 6 seconds from the body when traveling at Vo,
s = 24 m
24 = Vo(6) +(1/2)a(6^2)
24 = 6Vo +18a
4 = Vo +3a --------------(1)

At the 11th second, or 11 seconds from the body when traveling at Vo,
s = 24 +44 = 68 m
68 = Vo(11) +(1/2)a(11^2)
136 = 22Vo +121a -------------(2)

You have 2 independent equations with two unknowns. Solve them simultaneously and you should get
a = 48/55 m/sec/sec
Vo = 4 -3a = 76/55 m/sec

No time to check in details. Gotta go. If something is wrong, I'd get to that in about 11 hours or later. Sorry.