Problem:Which point on the parabola $\displaystyle y = x^2$ is nearest to (4, 0)? Find the coordinates to two decimals. (Hint: Minimize the square of the distance to avoid square roots.)

What I've Done:

I drew a picture to try and help me solve it, and tried to make a triangle between the curve $\displaystyle x^2$ and

the point (4 , 0). I just don't really know how to get any equations for the problem.

Help? I'd really appreciate it!