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Math Help - integral problem

  1. #1
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    integral problem

    This problem has me stumped:

    Find the exact area of the region:

    Bounded by y=(1)/(sqrt(x^2+9)), y=0, x=0, x=3

    I'm a little rusty on trigonometric substitutions
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  2. #2
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    Quote Originally Posted by Nitz456 View Post
    This problem has me stumped:

    Find the exact area of the region:

    Bounded by y=(1)/(sqrt(x^2+9)), y=0, x=0, x=3

    I'm a little rusty on trigonometric substitutions
    Are you wanting:

    0 = int(1/(sqrt(x^2 + 9))dx), from x = 0...3, in which case this is not possible.

    The integral is ln(sqrt(2) + 1), and this will never equal 0.
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  3. #3
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    Quote Originally Posted by AfterShock View Post
    Are you wanting:

    0 = int(1/(sqrt(x^2 + 9))dx), from x = 0...3, in which case this is not possible.

    The integral is ln(sqrt(2) + 1), and this will never equal 0.

    What I'm looking for, I'm quite sure, is the area of the integral of the equation i was given, for 0..3.

    i think the y=0 is just meaning that it doesnt want the integral below the x-axis.
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