# Math Help - Find the absolute maximum and absolute minimum values of the function

1. ## Find the absolute maximum and absolute minimum values of the function

Find the absolute maximum and absolute minimum values of the function on the interval [-2,9]:

f(x)= (x^3)/3-6x^2+35x

f'(x)=x^2-12x+35

so...

f'(x)= x(x-12)+35

so critical numbers are x=12,-35 but the problem is asking for on the interval [-2,9]

2. Originally Posted by Asuhuman18
Find the absolute maximum and absolute minimum values of the function on the interval [-2,9]:

f(x)= (x^3)/3-6x^2+35x

f'(x)=x^2-12x+35

so...

f'(x)= x(x-12)+35

so critical numbers are x=12,-35 ... no and no.
you know better, don't you?

$x^2 - 12x + 35 = 0$

( $x - 5)(x - 7) = 0$

try again.

3. so many simple mistakes sorry