Find the absolute maximum and absolute minimum values of the function on the interval [-2,9]: f(x)= (x^3)/3-6x^2+35x f'(x)=x^2-12x+35 so... f'(x)= x(x-12)+35 so critical numbers are x=12,-35 but the problem is asking for on the interval [-2,9]
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Originally Posted by Asuhuman18 Find the absolute maximum and absolute minimum values of the function on the interval [-2,9]: f(x)= (x^3)/3-6x^2+35x f'(x)=x^2-12x+35 so... f'(x)= x(x-12)+35 so critical numbers are x=12,-35 ... no and no. you know better, don't you? ( try again.
so many simple mistakes sorry
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