# Find the absolute maximum and absolute minimum values of the function

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• Nov 8th 2009, 02:29 PM
Asuhuman18
Find the absolute maximum and absolute minimum values of the function
Find the absolute maximum and absolute minimum values of the function on the interval [-2,9]:

f(x)= (x^3)/3-6x^2+35x

f'(x)=x^2-12x+35

so...

f'(x)= x(x-12)+35

so critical numbers are x=12,-35 but the problem is asking for on the interval [-2,9]
• Nov 8th 2009, 02:44 PM
skeeter
Quote:

Originally Posted by Asuhuman18
Find the absolute maximum and absolute minimum values of the function on the interval [-2,9]:

f(x)= (x^3)/3-6x^2+35x

f'(x)=x^2-12x+35

so...

f'(x)= x(x-12)+35

so critical numbers are x=12,-35 ... no and no.

you know better, don't you?

$x^2 - 12x + 35 = 0$

( $x - 5)(x - 7) = 0$

try again.
• Nov 8th 2009, 02:52 PM
Asuhuman18
so many simple mistakes sorry