f(t)=6^(2/3)+t^(5/3)

I understand I take the derivative of the function and set it equal to zero to find the critical numbers, however I get stuck after I take the derivative

f'(t)=4t^(-1/3)+5/3t^(2)=0

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- Nov 8th 2009, 01:34 PMAsuhuman18The critical numbers of the function
f(t)=6^(2/3)+t^(5/3)

I understand I take the derivative of the function and set it equal to zero to find the critical numbers, however I get stuck after I take the derivative

f'(t)=4t^(-1/3)+5/3t^(2)=0 - Nov 8th 2009, 01:53 PMskeeter
- Nov 8th 2009, 02:16 PMAsuhuman18