f(t)=6^(2/3)+t^(5/3)

I understand I take the derivative of the function and set it equal to zero to find the critical numbers, however I get stuck after I take the derivative

f'(t)=4t^(-1/3)+5/3t^(2)=0

Printable View

- Nov 8th 2009, 12:34 PMAsuhuman18The critical numbers of the function
f(t)=6^(2/3)+t^(5/3)

I understand I take the derivative of the function and set it equal to zero to find the critical numbers, however I get stuck after I take the derivative

f'(t)=4t^(-1/3)+5/3t^(2)=0 - Nov 8th 2009, 12:53 PMskeeter
- Nov 8th 2009, 01:16 PMAsuhuman18