f(t)=6^(2/3)+t^(5/3)
I understand I take the derivative of the function and set it equal to zero to find the critical numbers, however I get stuck after I take the derivative
f'(t)=4t^(-1/3)+5/3t^(2)=0
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f(t)=6^(2/3)+t^(5/3)
I understand I take the derivative of the function and set it equal to zero to find the critical numbers, however I get stuck after I take the derivative
f'(t)=4t^(-1/3)+5/3t^(2)=0
I guess you meant f(t) to be ...Quote:
Originally Posted by Asuhuman18
can you finish?
yeah sorry about that...Thanks for all the helpQuote:
Originally Posted by skeeterI guess you meant f(t) to be ...
can you finish?