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Math Help - Integrals and Indefinite Integrals

  1. #1
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    Integrals and Indefinite Integrals

    1) Evaluate the integral: \int^5_4(y-2)(2y+3) = \int^5_42y^2-y-6

    Antiderivative of the fucntion is f(x) = \frac{2y^3}{3} - \frac{y^2}{2}-6y

    So the answer is f(5)-f(4) = 40.8333-22.6666.

    Have a feeling I messed up on this one.

    2) Evaluate the Integral \int^6_1 \frac{1}{3x} = \int^6_1 (3x)^{-1}

    Antiderivative of the fucntion being integrated is ln(3x) so the answer is ln(18)-ln(3)

    3) Evaluate the indefinite integral:

    18t-t^2+3t^3-\frac{t^4}{4}+C
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  2. #2
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    Bump.
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  3. #3
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    Quote Originally Posted by Open that Hampster! View Post
    Have a feeling I messed up on this one.
    f should be a function of y
    Quote Originally Posted by Open that Hampster! View Post
    2) Evaluate the Integral \int^6_1 \frac{1}{3x} = \int^6_1 (3x)^{-1}

    Antiderivative of the fucntion being integrated is ln(3x) so the answer is ln(18)-ln(3)
    No way, \int^a_b\frac{1}{cx} = \frac{\ln a - \ln b}{c}
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  4. #4
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    Quote Originally Posted by Skerven View Post
    f should be a function of y
    That was a typo. The answer is the problem.

    Thanks for the second one, though.
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