From the point (14,14) there are two tangent lines to the ellipse 3x^2+y^2=28. Find the coordinates of the two points of tangency.
So I started by using implicit differentiation to find dy/dx = -3x/y and we know that y = sqrt(28-3x^2) but I'm not sure what to do from here. Would I plug in y so that dy/dx = -3x/sqrt(28-3x^2)? If that is what you do then how does that help you find the coordinates?
Thanks in advance for help