# Thread: Integrating inverse trig functions

1. ## Integrating inverse trig functions

I have no idea how to get those fancy looking equations to show up on forums, so I'm just going to write it out.

It looks like I'll have to try to get it to look like the inverse secant, but after trying u-substitution with x^3, which looks like my only option, I-I get stuck. I have a feeling that I'm missing something really simple. A-any help is greatly appreciated.

2. Originally Posted by Lark
I have no idea how to get those fancy looking equations to show up on forums, so I'm just going to write it out.

It looks like I'll have to try to get it to look like the inverse secant, but after trying u-substitution with x^3, which looks like my only option, I-I get stuck. I have a feeling that I'm missing something really simple. A-any help is greatly appreciated.

try $u = x^6$

then $s = u - 1$

then $p = \sqrt{s}$

... or

http://www.wolframalpha.com/input/?i...sqrt((x^6)-1))

Good luck!

3. Originally Posted by apcalculus
try $u = x^6$

then $s = u - 1$

then $p = \sqrt{s}$

... or

http://www.wolframalpha.com/input/?i=integrate+3/(x*sqrt((x^6)-1))

Good luck!
Whoa! I'm sorry if I sound really dumb saying this haha, but um, I-I don't understand your answer at all! The model problem for this question was
and it was solved by u=x^2, which works out really nicely. I'm assuming that I need to solve the one I'm stuck on in the same way (b-because really, I don't know any other way haha). Sorry for being bothersome!

4. Originally Posted by Lark
Whoa! I'm sorry if I sound really dumb saying this haha, but um, I-I don't understand your answer at all! The model problem for this question was
and it was solved by u=x^2, which works out really nicely. I'm assuming that I need to solve the one I'm stuck on in the same way (b-because really, I don't know any other way haha). Sorry for being bothersome!
Did you use the given link and then click Show Steps?

5. @mr fantastic:

C-cripes, I didn't know you could show steps haha. Thanks for telling me. Problem solved. Thanks!

@apcalculus:

Ahhh thank you!