Determine the extreme values of each function on the given interval.

a) f(x)= 1 + (x+3)^2 , -2<=x<=6

This is my work:

Critical numbers of f'(x)=2(x+3)

1) f'(x)=0 when x=-3

Test Critical numbers & end points

f(-2)=2

f(6)=82

Abs max is 82 (this answer is correct with the back of the book)

Abs min is 2 (this answer is WRONG with the back of the book)

What did I do here that is wrong?

Would the local max be 82 at x=6 and the local min be 2 at x=-2?