Point on a Curve parallel to a line [Something Missing ?]

This is a question from a worksheet my teacher printed out of a book. It seems like something is missing because I don't know what to do with the question...

The point on the curve $\displaystyle y = \sqrt[2]{4x+2}$ at which the normal is parallel to the line $\displaystyle y=-x+8$ is

- (A) $\displaystyle (\frac{1}{4}, \sqrt[2]{2})$
- (B)$\displaystyle (\frac{-1}{2}, 0)$
- (C)$\displaystyle (0, \sqrt[2]{2})$
- (D)$\displaystyle (\frac{1}{2}, 2)$
- (E)$\displaystyle (1, \sqrt[2]{6})$