ln must operate on a value > 0 So I solved for the inequality: 2-5x>0 x>2/5 is this right? I graphed the function but the domain was x<2/5 I'm not sure what I'm doing wrong. Any help is appreciated.
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when u divide by (-5) on the inequality, the inequality signs flips so it would be x is less than 2/5 not greater than
Originally Posted by REWIND10 ln must operate on a value > 0 So I solved for the inequality: 2-5x>0 x>2/5 is this right? I graphed the function but the domain was x<2/5 I'm not sure what I'm doing wrong. Any help is appreciated. Dividing by a negative number reverses the sign of an inequality.
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