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Thread: Taylor approximation of cos

  1. #1
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    Taylor approximation of cos

    Calculate cos(.1) to seven decimal places.
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  2. #2
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    Quote Originally Posted by cgiulz View Post
    Calculate cos(.1) to seven decimal places.
    What are you having trouble with? Figuring out the series or how to get 7 decimal places?
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  3. #3
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    Here is where I am:

    Since R_{5} (.1) = |-\cos(c)| \frac{.1^{12}}{12!} \leq \frac{.1^{12}}{12!} < ...

    \cos(.1) = 1 - \frac{.1^2}{2!} + \frac{.1^4}{4!} - \frac{.1^6}{6!} + \frac{.1^8}{8!} - \frac{.1^{10}}{10!} + \frac{.1^{12}}{12!}

    Oh oops.. I was not accounting for the .1 in my error term, so that makes this allot simpler.
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