y= (sec x)^(x^4) i did ln y = x^4 (ln sec x) and then what do i have to do?
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Originally Posted by haebinpark y= (sec x)^(x^4) i did ln y = x^4 (ln sec x) and then what do i have to do? take the derivative ... $\displaystyle \frac{y'}{y} = x^4 \cdot \tan{x} + 4x^3 \ln(\sec{x})$ finish by multiplying both sides by $\displaystyle y$
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