Find the point on the line 3x + 2y -3 = 0, which is closest to the point (1, -3).
( , ) ?
Two hints: 1) (a,b) = (a,f(a)) where f(a) is the y-value for x=a
2) The distance formula has a nasty square-root. If you minimize D^2, you also minimize D. So you can drop the square root.
Differentiate and find critical point.