hi, i have to integrate the following expression:
3e^-.8t multiplied by sin(t)
i'm a little confused as to how to go about this, so if anyone could help i'd appreciate it!
The derivation is long the standard way. It is simpler with complex analysis but I assume you do not know that method. Thus, instead of deriving it I will just mention a formula,
For $\displaystyle a,b\not = 0$.
$\displaystyle \int e^{ax}\sin bx dx = \frac{e^{ax}}{a^2+b^2}(a\sin bx - b\cos bx)+C$