At what point on the given curve is the tangent line parallel to the line 3x-y= 3?

= 2 + 2ye− 3xx

get x and y.

what I did so far:

rearranged 3x=y=3 to get y=3x-3, which shows the slope is 3, so i need to find where my tangent line has a slope of 3 on the line 2+2e^x-3 i think.

How would i proceed? Thanks.