hello,

i am trying to evaluate

=lim(as x -->2) of {[1/(x-2)][integral from 2 to x of [(sint)/t]dt]}

i have tried with Leibniz' rule and now derived that

z= [integral from 2 to x of (sinx/x)dt} =>

dz/dx = (sinx)/x => z = integral of (sinx)/x

but then i am still at a loss as to how to evaluate

=lim(as x -->2) of {[1/(x-2)][integral of [(sinx)/x]dx]}

Pleasssssssseeeeeeee hlp(Bow)