This is, of course, . To do that integral, use integration by parts with , dv= dx.

These two curves intersect at (0,0) and (2,2) so this is [tex]\int_{x=0}^2 (2sin(\pi x/4)- 4 sin^{-1}(x/2)/4) dx.find the area of the region enclosed by the curves

y=2sin[(pi)x/4] and x=2sin[(pi)y/4]

You should be able to look up the integrals of both those functions.

thankyou =]