find the area between the curve y=tan-1x, the X axis and the line x=sqrt3
find the area of the region enclosed by the curves
y=2sin[(pi)x/4] and x=2sin[(pi)y/4]
thankyou =]
This is, of course, $\displaystyle \int_{x=0}^{\sqrt{3}} tan^{-1}(x) dx$. To do that integral, use integration by parts with $\displaystyle u= tan^{-1}(x)$, dv= dx.
These two curves intersect at (0,0) and (2,2) so this is [tex]\int_{x=0}^2 (2sin(\pi x/4)- 4 sin^{-1}(x/2)/4) dx.find the area of the region enclosed by the curves
y=2sin[(pi)x/4] and x=2sin[(pi)y/4]
You should be able to look up the integrals of both those functions.
thankyou =]