If siny=x and pi/2<y<pi, find dy/dx in terms of x
thank you for any help given.
hi im new, today was my first day being introduced into inverse trig. please tell me if i am incorrect as it would benefit both of us.
If siny=x and pi/2<y<pi, find dy/dx in terms of x
y is an angle and x is a ratio.
siny=x, pi/2 < y < pi, sin is positive in this domain.
so x'= cosy