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  1. #1
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    differentiation

    Please help!I am completely lost on this....
    Question:evaluate using(a) first principles(b)shorthand method
    -5x^5 + 2x^2/3 - 3x^-3/4 + x

    I dont know the formulas for this could someone do a sample question like this for me please?
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  2. #2
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    Quote Originally Posted by wolfhound View Post
    Please help!I am completely lost on this....
    Question:evaluate using(a) first principles(b)shorthand method
    -5x^5 + 2x^2/3 - 3x^-3/4 + x

    I dont know the formulas for this could someone do a sample question like this for me please?
    hard to tell what this function is w/o proper grouping symbols (parentheses).

    this is what you typed in ...

    y = -5x^5 + \frac{2x^2}{3} - \frac{3x^{-3}}{4} + x
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  3. #3
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    Quote Originally Posted by skeeter View Post
    hard to tell what this function is w/o proper grouping symbols (parentheses).

    this is what you typed in ...

    y = -5x^5 + \frac{2x^2}{3} - \frac{3x^{-3}}{4} + x
    hi its actually 2x to power 2/3(fraction) and after 3x to the power -3/4(fraction)
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  4. #4
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    Quote Originally Posted by wolfhound View Post
    hi its actually 2x to power 2/3(fraction) and after 3x to the power -3/4(fraction)

    y = -5x^5 + 2x^{2/3} - 3x^{-3/4} + x<br />

    use the power rule for derivatives, \frac{d}{dx} x^n = nx^{n-1} ...

    y' = -25x^4 + \frac{4}{3} x^{-1/3} + \frac{9}{4}x^{-7/4} + 1


    finding the derivative using first principles is going to be an algebra drill of epic proportions ... an unreasonable task imho.
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  5. #5
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    Quote Originally Posted by skeeter View Post
    y = -5x^5 + 2x^{2/3} - 3x^{-3/4} + x<br />

    use the power rule for derivatives, \frac{d}{dx} x^n = nx^{n-1} ...

    y' = -25x^4 + \frac{4}{3} x^{-1/3} + \frac{9}{4}x^{-7/4} + 1


    finding the derivative using first principles is going to be an algebra drill of epic proportions ... an unreasonable task imho.
    Thank you
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