1. ## differentiation

Question:evaluate using(a) first principles(b)shorthand method
-5x^5 + 2x^2/3 - 3x^-3/4 + x

I dont know the formulas for this could someone do a sample question like this for me please?

2. Originally Posted by wolfhound
Question:evaluate using(a) first principles(b)shorthand method
-5x^5 + 2x^2/3 - 3x^-3/4 + x

I dont know the formulas for this could someone do a sample question like this for me please?
hard to tell what this function is w/o proper grouping symbols (parentheses).

this is what you typed in ...

$y = -5x^5 + \frac{2x^2}{3} - \frac{3x^{-3}}{4} + x$

3. Originally Posted by skeeter
hard to tell what this function is w/o proper grouping symbols (parentheses).

this is what you typed in ...

$y = -5x^5 + \frac{2x^2}{3} - \frac{3x^{-3}}{4} + x$
hi its actually 2x to power 2/3(fraction) and after 3x to the power -3/4(fraction)

4. Originally Posted by wolfhound
hi its actually 2x to power 2/3(fraction) and after 3x to the power -3/4(fraction)

$y = -5x^5 + 2x^{2/3} - 3x^{-3/4} + x
$

use the power rule for derivatives, $\frac{d}{dx} x^n = nx^{n-1}$ ...

$y' = -25x^4 + \frac{4}{3} x^{-1/3} + \frac{9}{4}x^{-7/4} + 1$

finding the derivative using first principles is going to be an algebra drill of epic proportions ... an unreasonable task imho.

5. Originally Posted by skeeter
$y = -5x^5 + 2x^{2/3} - 3x^{-3/4} + x
$

use the power rule for derivatives, $\frac{d}{dx} x^n = nx^{n-1}$ ...

$y' = -25x^4 + \frac{4}{3} x^{-1/3} + \frac{9}{4}x^{-7/4} + 1$

finding the derivative using first principles is going to be an algebra drill of epic proportions ... an unreasonable task imho.
Thank you