Define h: R-> R by h(x) = { x^2, x is rational { 0, x is irrational Prove that H is differentiable at 0. How would you do this? Thanks!
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Originally Posted by Sterwine Define h: R-> R by h(x) = { x^2, x is rational { 0, x is irrational Prove that H is differentiable at 0. How would you do this? Thanks! Show that the function is continuous and smooth at $\displaystyle x = 0$.
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