could someone please please tell me how to integrate
dx/dt = (x^3).(e^t)
intial condition : x(1) = -4
this looks v.simple but trust me, its not!
help me out! aaaah...
thank you
$\displaystyle x(1)=-4$ so when t=1, x=-4
$\displaystyle
-\frac{1}{2(-4)^2}=e^1+c
$
$\displaystyle -\frac{1}{32}=e+c$
So $\displaystyle c=-e-\frac{1}{32}$
And the solution is
$\displaystyle -\frac{1}{2x^2}=e^t-e-\frac{1}{32}$
which can be combined or manipulated or whatever you wanna do but I'll leave it like that