Compute [(2h + hg)/(g^2+1)] (0), where g is the function below
f(x) = x sin(1/x), x not = 0
f(x) = 0, x = 0
g(x) = xf(x).
Define h : R - R by
h(x) = {x^2, x rational
h(x) = {0, x irrational
I do not even understand the question, can anyone help
Compute [(2h + hg)/(g^2+1)] (0), where g is the function below
f(x) = x sin(1/x), x not = 0
f(x) = 0, x = 0
g(x) = xf(x).
Define h : R - R by
h(x) = {x^2, x rational
h(x) = {0, x irrational
I do not even understand the question, can anyone help