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Thread: help with computation

  1. #1
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    help with computation

    Compute [(2h + hg)/(g^2+1)] (0), where g is the function below
    f(x) = x sin(1/x), x not = 0
    f(x) = 0, x = 0

    g(x) = xf(x).


    Define h : R - R by
    h(x) = {x^2, x rational
    h(x) = {0, x irrational

    I do not even understand the question, can anyone help
    Last edited by 450081592; Nov 3rd 2009 at 01:22 PM.
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  2. #2
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    Quote Originally Posted by 450081592 View Post
    Compute [(2h + hg)/(g^2+1)] (0), where g is the function below
    f(x) = x sin(1/x), x not = 0
    f(x) = 0, x = 0

    g(x) = xf(x).


    I do not even understand the question, can anyone help
    You haven't specified what $\displaystyle h(x)$ is.

    Are you sure you aren't trying to find

    $\displaystyle h(0) = \frac{2f(0) + g(0)f(0)}{g^2(0) + 1}$?
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  3. #3
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    Quote Originally Posted by Prove It View Post
    You haven't specified what $\displaystyle h(x)$ is.

    Are you sure you aren't trying to find

    $\displaystyle h(0) = \frac{2f(0) + g(0)f(0)}{g^2(0) + 1}$?
    sorry, I forget to rewrite the function

    Define h : R - R by
    h(x) = {x^2, x rational
    h(x) = {0, x irrational

    I think we should use the quotient rule here, but I dont know how to start it
    Last edited by 450081592; Nov 3rd 2009 at 01:21 PM.
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