Compute [(2h + hg)/(g^2+1)] (0), where g is the function below f(x) = x sin(1/x), x not = 0 f(x) = 0, x = 0 g(x) = xf(x). Define h : R - R by h(x) = {x^2, x rational h(x) = {0, x irrational I do not even understand the question, can anyone help
Last edited by 450081592; Nov 3rd 2009 at 01:22 PM.
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Originally Posted by 450081592 Compute [(2h + hg)/(g^2+1)] (0), where g is the function below f(x) = x sin(1/x), x not = 0 f(x) = 0, x = 0 g(x) = xf(x). I do not even understand the question, can anyone help You haven't specified what is. Are you sure you aren't trying to find ?
Originally Posted by Prove It You haven't specified what is. Are you sure you aren't trying to find ? sorry, I forget to rewrite the function Define h : R - R by h(x) = {x^2, x rational h(x) = {0, x irrational I think we should use the quotient rule here, but I dont know how to start it
Last edited by 450081592; Nov 3rd 2009 at 01:21 PM.
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