Compute [(2h + hg)/(g^2+1)] (0), where g is the function below

f(x) = x sin(1/x), x not = 0

f(x) = 0, x = 0

g(x) = xf(x).

Define h : R - R by

h(x) = {x^2, x rational

h(x) = {0, x irrational

I do not even understand the question, can anyone help

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- Nov 2nd 2009, 05:45 PM450081592help with computation
Compute [(2h + hg)/(g^2+1)] (0), where g is the function below

f(x) = x sin(1/x), x not = 0

f(x) = 0, x = 0

g(x) = xf(x).

Define h : R - R by

h(x) = {x^2, x rational

h(x) = {0, x irrational

I do not even understand the question, can anyone help - Nov 2nd 2009, 05:57 PMProve It
- Nov 2nd 2009, 07:21 PM450081592