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**qbkr21** If a ball is thrown straight up into the air with an initial velocity of $\displaystyle 50 ft/s$, its height in feet after t second is given by $\displaystyle y = 50 t - 16 t^2$. Find the average velocity for the time period beginning when $\displaystyle t = 1$ and lasting:

(i) $\displaystyle 0.1$ seconds =16.4 i.e., over the time interval $\displaystyle [1,1.1]$

(ii) $\displaystyle 0.01$ seconds=17.84

(iii) $\displaystyle 0.001$ seconds=17.984

Finally based on the above results, guess what the instantaneous velocity of the ball is when $\displaystyle t=1$$\displaystyle ?$