Intragral from 0 to 2pi e^cos(theta)8cos(ntheta-sine(theta)dtheta=2pi/n! where n=1,2,....

I got that cos(n(theta)-sin(theta))=e^i(ntheta-sin(theta))+e^-i(ntheta-sin(theta))

and now i don't know where to go from there?

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- November 2nd 2009, 09:01 AMbookie88Trig integrals
Intragral from 0 to 2pi e^cos(theta)8cos(ntheta-sine(theta)dtheta=2pi/n! where n=1,2,....

I got that cos(n(theta)-sin(theta))=e^i(ntheta-sin(theta))+e^-i(ntheta-sin(theta))

and now i don't know where to go from there?