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**warriors837** Let *f* be the function given by f(x)=3cosx. The graph of f crosses the y-axis at point P (0,3) and x-axis at point Q (pi/2,0).

**Find the x coordinate of the point of the graph f, between points P and Q, at which the line tangent to the graph of f is parallel to the line PQ.**

I found the equation for line PQ:

y-3=(-6/pi)x

And the equation for the line tangent to f at point Q:

y=-3[x-(pi/2)]

But I can't find the x-coordinate (the bolded part), i know that the slope is (-6/pi) and you set that equal to -3sinx, but i got an x-coordinate of sin^(-1)(2/pi). But I am supposed to do it all by hand and I don't think that is a valid answer.