The linear approximation at x = 0 to f(x) = sqrt (7 + 7 x) is y = any help will be appreciated!!
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Originally Posted by frozenflames The linear approximation at x = 0 to f(x) = sqrt (7 + 7 x) is y = any help will be appreciated!! see your other post ... http://www.mathhelpforum.com/math-he...gent-line.html
Originally Posted by skeeter see your other post ... http://www.mathhelpforum.com/math-he...gent-line.html i use the same approach and get the following: .1889822x+2.64575 but it is incorrect. any thoughts?
Originally Posted by frozenflames i use the same approach and get the following: .1889822x+2.64575 but it is incorrect. any thoughts? first of all, put away the calculator. your slope is wrong what did you get for f'(x) ?
Originally Posted by skeeter first of all, put away the calculator. your slope is wrong what did you get for f'(x) ? I get 1/(2*sqrt (7+7x)
Originally Posted by frozenflames I get 1/(2*sqrt (7+7x) you forgot the chain rule ... bad juju!
ofcourse!! i'm forgetting the inner and multiply by 7
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